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Jan 17th 2012 Math Test

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Jan 17th 2012 Math Test - Tue Jan 17, 2012, 05:01 AM
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XXChris123's Avatar
Since: Jul 2010
Posts: 1,512
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The product N of three positive integers is 6 times their sum , and one of the integers is the sum of the other two.
Find the sum of all possible values of N .

product N of 3 positive integers
A x B x C = N

is 6 times their sum ,
= 6 ( A + B + C )

and one of the integers is the sum of the other two.
A + B = C

Find the sum of possible values of N

A x B x C = N = 6 ( A+ B+ C )
A + B = C so A+ B = A+ B
A x B = AB

AB ( A+ B) = N = 6 ( A + B + A + B ) ...............A+ B is substituted for all C's see A+B = C

AB ( A + B ) = 6 ( 2A + 2B ) = N
AB ( A + B ) = 12 ( A + B ) = N

divide both sides by ( A + B ).
AB ( A + B ) / ( A + B ) = 12 ( A + B ) / ( A+ B ) =
AB = 12 = N

..........................Product of 3 + integers.........6 ( A+ B + C)
A + B = C ....................AB(C) = N..................
1 + 12 = 13 ........ 12 X 13 = 156........... 6 ( 1 +12 +13 ) = 6 x 26 = 156
2 + 6 = 8 ..........2 x 6 X 8 = 96............6 ( 2 + 6 + 8 ) = 6 x 16 = 96
3 + 4 = 7 ..........3 x 4 x 7 = 84 ............6 ( 3 + 4 + 7 ) = 6 x 14 = 84


Find the sum of possible values of N

156 + 96 + 84 = 336

Last edited by XXChris123; Wed Jan 18, 2012 at 12:22 AM..
 
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Tue Jan 17, 2012, 11:06 AM
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mtnestegg's Avatar
Since: Feb 2011
Posts: 1,336
Pemdas
 
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Tue Jan 17, 2012, 12:13 PM
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Yawni's Avatar
Since: Aug 2010
Posts: 161
N=6
A=1
B=2
C=3

Not great at math, but my best guess

Yawni

Last edited by Yawni; Tue Jan 17, 2012 at 12:43 PM.. Reason: Nope I'm wrong
 
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Tue Jan 17, 2012, 10:16 PM
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TrustySam's Avatar
Since: Aug 2010
Posts: 8,291
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Oh these are great

I really liked your birdhouse with the picket fence on it too

(I got 3 sets of possible numbers for A,B,C - is that what you got? )
 
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Tue Jan 17, 2012, 11:28 PM
(#5)
XXChris123's Avatar
Since: Jul 2010
Posts: 1,512
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very good Sam guess I will repost it

video of the math problem

http://www.khanacademy.org/video/200...etition%20Math

Last edited by XXChris123; Wed Jan 18, 2012 at 12:13 AM..
 
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Wed Jan 18, 2012, 02:13 AM
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TrustySam's Avatar
Since: Aug 2010
Posts: 8,291
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Maybe people are just shy about like, oh geez, did I do it okay? Is my answer right? Is it part right? Sort of?

They're getting harder pretty fast! But nice to be able to try and stuff
 
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Wed Jan 18, 2012, 08:14 AM
(#7)
XXChris123's Avatar
Since: Jul 2010
Posts: 1,512
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I can do a range
maybe I should back pedal
If nothing else I want to raise players math skills to the point they can do all the math
behind poker
 

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