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Odds help!!

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Odds help!! - Sat Nov 23, 2002, 08:22 AM
(#1)
Deleted user
I have learned a little about odds on my own from reading posts here and at other places, but I just can't figure this one out. Any help would be greatly appreciated. Lets just say you have a four flush on the flop and nothing else, how do you figure the odds to see if one of the next 2 cards will be your suit??????

thanks, torax
 
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Sat Nov 23, 2002, 08:44 AM
(#2)
TrumpinJoe's Avatar
Since: Jun 2010
Posts: 4,557
With 4 of a suit and 5 known cards there are 9 outs of 47 cards for the turn. The river will have 9 outs of 46 cards. You figure the probability of an event NOT occuring so:

(47-9)/47 = 38/47 = .8085 is the probability you won't see your suit on the turn, and:

(46-9)/46 = 37/46 = .8043 for the river.

he combined probability of each of these is:
.8085 * .8043 = .6503

meaning that 65% of the time yor flush DOES NOT make by the river. Conversely 35% of the time it does make. To figure the odds you use 65%/35% = 1.86:1 against
 
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Let's Simplify. - Tue Nov 26, 2002, 11:38 AM
(#3)
Deleted user
9 outs with 2 cards to come: multiply by 4!!

4 * 9 = 36% (chance to hit!!)

with 1 card to come, multiply by 2!

2 * 9 = 18% (18% chance)

Not exact - but easy to use at the table!!
 

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