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Fold equity calc with mulitple villians

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Fold equity calc with mulitple villians - Wed Oct 30, 2013, 08:27 AM
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MolaSalo's Avatar
Since: Nov 2012
Posts: 26
Hey guys ,

I've already know how to calc pot odds,hand equity and fold equity.But I still struggle with the math when I have to count other villians % that they will fold.
I asked to my friend who's a pro mtt player and he said:First you have to estimate how x% they will fold,then you have a scenario like,villian A folds and villian B calls , A and B calls,A calls and B fold and both folds.But still i dont how to calculate it :/

Here's a hand example:
100/200 blinds.
Its folded to CO 3150(16bb) (30/22/100steal% from late pos from co to sb),he minraises,bu folds,I have A4o 3085 in sb(after posing the sb) and BB 1885 10 bb(31/25/50/100fold@bb from late pos steal).
Total pot before reshove :700


So my calc against the min raiser if i reshove:

1. (Villian fold% against reshove) x (tot pot)=A
I expect him to fold 85% of the time.

2.(villian call%) x (my win equity in % when gets called)= x1

3.(villian call %) - x1 = x2

4.x1 x(pot win tot) = x3
x2 x (pot lose tot) = x4

5 A + x3 -x4
I expect that most of the time we lost a pot,we get a negative outcome.

The math against reshove (without counting the palyer at bb)

1. 0.85x 700= 595

2. 0.15 x 0.388 = 0.0582

3 0.15- 0.0582 = 0.0918

4. 0.0582 x 4220= 245
0.0918 x -3085 = -283

5. 595 + 245 - 283 = 557

At least this is a profitable reshove against the player who min raised. I also used pokerstove in this math btw .

But how do you guys count the Big Blind in the math ?
 

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